Copper (II) loses 2 electrons, so it has a charge of 2+ Copper (I) loses 1 electron, so it has a charge of 1+ Sulfate is SO42- ...So.... Copper (II) sulfate --> Cu2+ + SO42-= CuSO4 Copper (I) sulfate --> Cu+ + SO42- = (Cu)2SO4 [this uses the criss-cross method]
Nestor. Please re-read the question. You only partially answered it.
Type 1 binary ionic compounds have cation that has only one form or charge, type 2 binary ionic compounds have cation that can have multiple forms.
Copper (II) loses 2 electrons, so it has a charge of 2+
Copper (I) loses 1 electron, so it has a charge of 1+
Sulfate is SO42-
...So....
Copper (II) sulfate --> Cu2+ + SO42-= CuSO4
Copper (I) sulfate --> Cu+ + SO42- = (Cu)2SO4 [this uses the criss-cross method]
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